Sulphur trioxide is dissolved in heavy water | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,it forms deuterated sulphuric acid $(D_2SO_4)$ as the compound $X$.The chemical reaction is: $SO_

Vedclass · Accepted Answer

$sp^3$

Vedclass · Answer

(B) When $SO_3$ is dissolved in heavy water $(D_2O)$,it forms deuterated sulphuric acid $(D_2SO_4)$ as the compound $X$.The chemical reaction is: $SO_3 + D_2O \longrightarrow D_2SO_4$ $(X)$.In $D_2SO_4$,the central sulphur atom is bonded to two $OD$ groups and two oxygen atoms via double bonds.The steric number of sulphur is calculated as: $	ext{Number of sigma bonds} + 	ext{Number of lone pairs} = 4 + 0 = 4$.$A$ steric number of $4$ corresponds to $sp^3$ hybridisation.

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

Similar Questions

Why is the bond angle in $CH_4$ not $90^{\circ}$,even though the outermost $p$-orbitals of carbon are at $90^{\circ}$ to each other?

Is there any change in the hybridization of $B$ and $N$ atoms as a result of the following reaction? $BF_3 + NH_3 \to F_3B \cdot NH_3$

In the formation of a certain compound,the central atom uses its hybrid orbitals and has a bond angle around it of $105^o$. The percentage of $s-$ character in the hybrid orbitals is likely to be

In $C_{60}$,all carbon atoms are:

What type of hybridization is present in the $PCl_{5}$ molecule?

Vedclass Test Series

Exam Paper Generator

Online Exam Module