(B) The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n-1)d$.Given,$T_{20} = 40$ and $d = 2$.Substituting the values: $40 = a + (20-1)2$.$

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(B) The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n-1)d$.Given,$T_{20} = 40$ and $d = 2$.Substituting the values: $40 = a + (20-1)2$.$40 = a + 19 \times 2$.$40 = a + 38$.$a = 40 - 38 = 2$.Now,the second term $T_2 = a + d$.$T_2 = 2 + 2 = 4$.Therefore,the second term is $4$.

Class 10 Mathematics Arithmetic Progressions nth Term of an AP

Medium

The $20^{th}$ term of an $A.P.$ is $40$ and the common difference is $2$. Then,its second term is $\ldots \ldots \ldots \ldots$

A
$2$
B
$4$
C
$6$
D
$0$

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Class 10 Questions

Class 10

Mathematics Questions

Chapter

Arithmetic Progressions

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nth Term of an AP

The $20^{th}$ term of the $A.P.$ $2, -2, -6, -10, \ldots$ is.......

Medium

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Which term of the $AP: 3, 15, 27, 39, \ldots$ will be $132$ more than its $54^{th}$ term?

Difficult

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Find the $12^{\text{th}}$ term from the end of the $AP: -2, -4, -6, \ldots, -100$.

Medium

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Which term of the $A.P.$ $5, 15, 25, \ldots$ exceeds its $31^{st}$ term by $130$ (in $^{th}$)?

Medium

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How many numbers lie between $10$ and $300,$ which when divided by $4$ leave a remainder $3?$

Medium

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The $20^{th}$ term of an $A.P.$ is $40$ and the common difference is $2$. Then,its second term is $\ldots \ldots \ldots \ldots$

Similar Questions

The $20^{th}$ term of the $A.P.$ $2, -2, -6, -10, \ldots$ is.......

Which term of the $AP: 3, 15, 27, 39, \ldots$ will be $132$ more than its $54^{th}$ term?

Find the $12^{\text{th}}$ term from the end of the $AP: -2, -4, -6, \ldots, -100$.

Which term of the $A.P.$ $5, 15, 25, \ldots$ exceeds its $31^{st}$ term by $130$ (in $^{th}$)?

How many numbers lie between $10$ and $300,$ which when divided by $4$ leave a remainder $3?$

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