The angle between the pair of straight lines | vedclass

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Question

(A) The given equation of the pair of straight lines is $3y^2 - 8xy - 3x^2 - 29x + 3y - 18 = 0$. Rearranging the terms,we have $-3x^2 - 8xy + 3y^2 - 2

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(A) The given equation of the pair of straight lines is $3y^2 - 8xy - 3x^2 - 29x + 3y - 18 = 0$. Rearranging the terms,we have $-3x^2 - 8xy + 3y^2 - 29x + 3y - 18 = 0$. Comparing this with the general equation of a pair of straight lines $ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0$,we get $a = -3$ and $b = 3$. Since the sum of the coefficients of $x^2$ and $y^2$ is $a + b = -3 + 3 = 0$,the lines are perpendicular to each other. Therefore,the angle between the pair of straight lines is $90^{\circ}$.

The angle between the pair of straight lines $3y^2 - 8xy - 3x^2 - 29x + 3y - 18 = 0$ is (in $^{\circ}$)

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