The angle of an equilateral prism is $60^o$. What should be the refractive index of the prism so that the ray is parallel to the base inside the prism?

$A$ ray of light is incident normally on a prism of refractive index $1.5$,as shown. The prism is immersed in a liquid of refractive index $\mu$. The largest value of the angle $ACB$ such that the ray is totally internally reflected at the face $AC$ is $30^o$. Then the value of $\mu$ must be :

$A$ flint glass prism and a crown glass prism are to be combined in such a way that the deviation of the mean ray is zero. The refractive indices of flint and crown glasses for the mean ray are $1.620$ and $1.518$ respectively. If the refracting angle of the flint prism is $6.0^{\circ}$,what would be the refracting angle of the crown prism (in $^{\circ}$)?

$A$ given ray of light suffers minimum deviation in an equilateral prism $P$. Additional prisms $Q$ and $R$ of identical shape and material are now added to $P$ as shown in the figure. The ray will suffer

$A$ monochromatic beam of light is incident at $60^{\circ}$ on one face of an equilateral prism of refractive index $n$ and emerges from the opposite face making an angle $\theta(n)$ with the normal (see the figure). For $n=\sqrt{3}$ the value of $\theta$ is $60^{\circ}$ and $\frac{d \theta}{d n}=m$. The value of $m$ is

$A$ thin prism $P_1$ with angle $4^{\circ}$ made of glass having refractive index $1.54$ is combined with another thin prism $P_2$ made of glass having refractive index $1.72$ to produce dispersion without deviation. The angle of the prism $P_2$ in degrees is: