The angular speed of a particle moving in a circular path is doubled. Then, the centripetal acceleration of the particle is

The force required to keep a body in uniform circular motion is:

$A$ uniform circular disc of radius $50\, cm$ at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of $2.0\, rad \,s^{-2}$. Its net acceleration in $m\,s^{-2}$ at the end of $2.0\,s$ is approximately (in $.0$)

The centripetal acceleration is given by

In a hypothetical ring-shaped satellite rotating in space, artificial gravity can be achieved using centripetal force. If the satellite has a radius of $10 \,m$, then to achieve a centripetal acceleration at a point on the circumference of $10 \,ms^{-2}$, its angular speed is:

$A$ disc is rotating with constant angular velocity $\omega$ about an axis passing through centre $C$ and perpendicular to the plane of the disc. An insect is moving over the disc along the radial direction with constant velocity $v$ with respect to the disc. The acceleration of the insect at the instant when its distance from the centre is $r$ will be :-