The area of a circle is 3850 , cm^2. In that | vedclass

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(A) Given,the area of the circle $A = 3850 \, cm^2$.We know that the area of a circle is given by $A = \pi r^2$.So,$\pi r^2 = 3850$.Taking $\pi = \fra

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$55$

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(A) Given,the area of the circle $A = 3850 \, cm^2$.We know that the area of a circle is given by $A = \pi r^2$.So,$\pi r^2 = 3850$.Taking $\pi = \frac{22}{7}$,we have $\frac{22}{7} 	imes r^2 = 3850$.$r^2 = \frac{3850 	imes 7}{22} = 175 	imes 7 = 1225$.$r = \sqrt{1225} = 35 \, cm$.The length of an arc subtending an angle $	heta$ at the centre is given by $L = \frac{	heta}{360^\circ} 	imes 2 \pi r$.Here,$	heta = 90^\circ$ (right angle).$L = \frac{90^\circ}{360^\circ} 	imes 2 	imes \frac{22}{7} 	imes 35$.$L = \frac{1}{4} 	imes 2 	imes 22 	imes 5 = \frac{220}{4} = 55 \, cm$.

The area of a circle is $3850 \, cm^2$. In that circle,the length of an arc subtending a right angle at the centre is $\ldots \ldots \ldots \, cm$.

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