(C) The area of a trapezium is given by the formula: $\text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times (\text{height})$.Let the

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(C) The area of a trapezium is given by the formula: $\text{Area} = \frac{1}{2} \times (\text{sum of parallel sides}) \times (\text{height})$.Let the parallel sides be $5x$ and $3x$.The height (perpendicular distance) is $24 \, m$.Substituting the values into the formula:$1440 = \frac{1}{2} \times (5x + 3x) \times 24$$1440 = \frac{1}{2} \times (8x) \times 24$$1440 = 4x \times 24$$1440 = 96x$$x = \frac{1440}{96} = 15$.The larger parallel side is $5x = 5 \times 15 = 75 \, m$.

Competitive Quantitative Aptitude Mensuration Measurement of Area

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The area of a field in the shape of a trapezium is $1440 \, m^2$. The perpendicular distance between its parallel sides is $24 \, m$. If the ratio of the parallel sides is $5:3$, the length of the larger parallel side is ....... $m$.

A
$45$
B
$60$
C
$75$
D
$120$

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Measurement of Area

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The area of a field in the shape of a trapezium is $1440 \, m^2$. The perpendicular distance between its parallel sides is $24 \, m$. If the ratio of the parallel sides is $5:3$, the length of the larger parallel side is ....... $m$.

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The length and breadth of a rectangular piece of land are in the ratio $5:3$. The owner spent ₹ $6000$ for fencing it from all sides at the rate of ₹ $7.50$ per metre. The difference between its length and breadth is (in metres):

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