(A) The area of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula: $\text{Area} = \frac{1}{2} |x_1(y_2 - y_3

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(A) The area of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by the formula: $\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$. Substituting the given vertices $(1, -1)$,$(-1, 1)$,and $(-1, -1)$: $\text{Area} = \frac{1}{2} |1(1 - (-1)) + (-1)(-1 - (-1)) + (-1)(-1 - 1)|$ $= \frac{1}{2} |1(2) + (-1)(0) + (-1)(-2)|$ $= \frac{1}{2} |2 + 0 + 2|$ $= \frac{1}{2} |4| = 2$. Thus,the area is $2$ square units.

Class 12 Mathematics 3-4. Matrices and Determinants Expansion of determinants, Solution of equation in the form of determinants and area of triangle and Equation of Line

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The area of a triangle whose vertices are $(1, -1)$,$(-1, 1)$,and $(-1, -1)$ is given by

A
$2$
B
$0.5$
C
$1$
D
$3$

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Expansion of determinants, Solution of equation in the form of determinants and area of triangle and Equation of Line

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MediumAP EAMCET 2017

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The area of a triangle whose vertices are $(1, -1)$,$(-1, 1)$,and $(-1, -1)$ is given by

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