The areas of two square fields are 420.25 ; m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the sides of the two square fields be $s_1$ and $s_2$ respectively.Given that the area of the first square is $A_1 = 420.25 \; m^2$ and the ar

Vedclass · Accepted Answer

$41:42$

Vedclass · Answer

(C) Let the sides of the two square fields be $s_1$ and $s_2$ respectively.Given that the area of the first square is $A_1 = 420.25 \; m^2$ and the area of the second square is $A_2 = 441 \; m^2$.The side of a square is given by the formula $s = \sqrt{A}$.Therefore,$s_1 = \sqrt{420.25} = 20.5 \; m$ and $s_2 = \sqrt{441} = 21 \; m$.The ratio of their sides is $s_1 : s_2 = 20.5 : 21$.To simplify the ratio,multiply both terms by $2$: $(20.5 	imes 2) : (21 	imes 2) = 41 : 42$.

The areas of two square fields are $420.25 \; m^2$ and $441 \; m^2,$ respectively. The ratio of their sides is

Similar Questions

What should come in place of both the question marks in the equation $\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$?

The largest number of five digits which is a perfect square is

$\sqrt{176+\sqrt{2401}} = ?$

If $\sqrt{1+\frac{x}{961}}=\frac{32}{31},$ then the value of $x$ is

The value of $\sqrt{\frac{0.16}{0.4}}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module