The chance of throwing a total of 7 or 12 wit | vedclass

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(D) Total number of possible outcomes when rolling $2$ dice is $6 	imes 6 = 36$.For the sum to be $7$,the favorable outcomes are $(1, 6), (2, 5), (3,

Vedclass · Accepted Answer

$\frac{7}{36}$

Vedclass · Answer

(D) Total number of possible outcomes when rolling $2$ dice is $6 	imes 6 = 36$.For the sum to be $7$,the favorable outcomes are $(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)$. There are $6$ such outcomes.For the sum to be $12$,the only favorable outcome is $(6, 6)$. There is $1$ such outcome.Since these are mutually exclusive events,the total probability is the sum of the individual probabilities:$P(7 	ext{ or } 12) = P(7) + P(12) = \frac{6}{36} + \frac{1}{36} = \frac{7}{36}$.

The chance of throwing a total of $7$ or $12$ with $2$ dice is:

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