$\log_a(1 + x)$ ના વિસ્તરણમાં $x^n$ નો સહગુણક શું છે?

  • A
    $\frac{(-1)^{n-1}}{n}$
  • B
    $\frac{(-1)^{n-1}}{n} \log_a e$
  • C
    $\frac{(-1)^{n-1}}{n} \log_e a$
  • D
    $\frac{(-1)^n}{n} \log_a e$

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Similar Questions

$\frac{1}{1 \cdot 3} + \frac{1}{2 \cdot 5} + \frac{1}{3 \cdot 7} + \frac{1}{4 \cdot 9} + \dots$ ની કિંમત શોધો.

જો $P = 1 + \frac{1}{2 \times 2} + \frac{1}{3 \times 2^{2}} + \dots$ અને $Q = \frac{1}{1 \times 2} + \frac{1}{3 \times 4} + \frac{1}{5 \times 6} + \dots$ હોય, તો

જો $1+\frac{\sqrt{3}-\sqrt{2}}{2 \sqrt{3}}+\frac{5-2 \sqrt{6}}{18}+\frac{9 \sqrt{3}-11 \sqrt{2}}{36 \sqrt{3}}+\frac{49-20 \sqrt{6}}{180}+\ldots$ અનંત સુધી $= 2\left(\sqrt{\frac{b}{a}}+1\right) \log _e\left(\frac{a}{b}\right)$,જ્યાં $a$ અને $b$ એ પૂર્ણાંકો છે અને $\operatorname{gcd}(a, b)=1$,તો $11 a+18 b$ ની કિંમત ............... થાય.

$\log_e [(1 + x)^{1 + x} (1 - x)^{1 - x}] = $

$1 + \frac{(\log_e n)^2}{2!} + \frac{(\log_e n)^4}{4!} + \dots = $

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