The coefficient of static friction,$\mu_s$ between block $A$ of mass $2\,kg$ and the table as shown in the figure is $0.2$. What would be the maximum mass value of block $B$ so that the two blocks do not move (in $,kg$)? The string and the pulley are assumed to be smooth and massless. $(g = 10\,m/s^2)$

Three rods $AB$,$BC$,and $BD$ made of the same material and having the same cross-section have been joined as shown in the figure. The ends $A$,$C$,and $D$ are held at temperatures of $20^{\circ}C$,$80^{\circ}C$,and $80^{\circ}C$ respectively. If each rod is of the same length,then the temperature at the junction $B$ of the three rods is: (in $^{\circ}C$)

A $6 \, V$ cell with $0.5 \, \Omega$ internal resistance, a $10 \, V$ cell with $1 \, \Omega$ internal resistance and a $12 \, \Omega$ external resistance are connected in parallel. The current (in ampere) through the $10 \, V$ cell is

$A$ resistor of $2 \Omega$,an inductor of $100 \mu H$,and a capacitor of $400 pF$ are connected in series across a source of $e_{rms} = 0.1 \text{ V}$. At resonance,the voltage drop across the inductor is: (in $\text{ V}$)

Assign $A, B, C, D$ from the given type of reaction.
$4KCN + Fe(CN)_2 \downarrow \longrightarrow K_4[Fe(CN)_6]$

Ammonia with excess of $Cl_2$ forms: