The combined equation of the diagonals of the square formed by the pairs of lines $xy+6y-4x-24=0$ and $xy+6x-4y-24=0$ is

The area of the triangle formed by the pair of straight lines $(ax+by)^2 - 3(bx-ay)^2 = 0$ and the line $ax+by+c = 0$ is

The orthocentre of the triangle formed by the lines $2x^2 - 3xy + y^2 = 0$ and $x + y = 1$ is

If the equations $3x^2 + 2hxy - 3y^2 = 0$ and $3x^2 + 2hxy - 3y^2 + 2x - 4y + c = 0$ represent the four sides of a square,then $\frac{h}{c} =$

If $d$ is the distance between the point of intersection of the lines $x^2+4xy+ky^2-4x-10y+3=0$ and the origin,and $p$ is the product of the perpendicular distances from the origin to these lines,then $d^2-20p^2=$

If the pair of straight lines given by $Ax^2+2Hxy+By^2=0$ $(H^2>AB)$ forms an equilateral triangle with the line $ax+by+c=0$,then $(A+3B)(3A+B)$ is equal to: