The conjugate of the complex number frac{2 - | vedclass

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(B) Let $z = \frac{2 - 3i}{4 - i}$.To simplify,multiply the numerator and denominator by the conjugate of the denominator,which is $4 + i$:$z = \frac{

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$\frac{11 + 10i}{17}$

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(B) Let $z = \frac{2 - 3i}{4 - i}$.To simplify,multiply the numerator and denominator by the conjugate of the denominator,which is $4 + i$:$z = \frac{(2 - 3i)(4 + i)}{(4 - i)(4 + i)}$$z = \frac{8 + 2i - 12i - 3i^2}{16 - i^2}$Since $i^2 = -1$,we have:$z = \frac{8 - 10i + 3}{16 + 1} = \frac{11 - 10i}{17}$The conjugate of $z = a + bi$ is $\bar{z} = a - bi$.Therefore,the conjugate of $\frac{11 - 10i}{17}$ is $\frac{11 + 10i}{17}$.

The conjugate of the complex number $\frac{2 - 3i}{4 - i}$ is

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