The coordinates of the point,where the line $\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+5}{4}$ meets the plane $2x+4y-z=3$,are

  • A
    $(3,-1,-1)$
  • B
    $(3,1,-1)$
  • C
    $(3,-1,1)$
  • D
    $(-3,-1,-1)$

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