The correct order of electron gain enthalpies | vedclass

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(D) The electron gain enthalpy $(\Delta_{eg}H)$ becomes less negative as we move down a group.
For Group $16$ ($Te$ and $Po$): The order is $Po <

Vedclass · Accepted Answer

$Po < Te < F < Cl$

Vedclass · Answer

(D) The electron gain enthalpy $(\Delta_{eg}H)$ becomes less negative as we move down a group.
For Group $16$ ($Te$ and $Po$): The order is $Po < Te$ (in terms of magnitude of negative value,$Te$ is more negative than $Po$).
For Group $17$ ($F$ and $Cl$): Due to the small size of $F$,the electron-electron repulsion is high,making $Cl$ have a more negative electron gain enthalpy than $F$.
The values are:
$Cl: -349 \ kJ/mol$
$F: -328 \ kJ/mol$
$Te: -190 \ kJ/mol$
$Po: -174 \ kJ/mol$
Comparing the magnitude of negative values (more negative means more energy released,i.e.,lower enthalpy value):
$Po (-174) < Te (-190) < F (-328) < Cl (-349)$.
Thus,the correct order of electron gain enthalpies is $Po < Te < F < Cl$.

The correct order of electron gain enthalpies of $Cl$,$F$,$Te$,and $Po$ is .....

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