The correct relation for the capillary rise $h$ in a tube of radius $r$ is:

When a capillary is dipped in water,water rises to a height $h$. If the length of the capillary is made less than $h$,then

$A$ vertical glass capillary tube of radius $r$ open at both ends contains some water (surface tension $T$ and density $\rho$). If $L$ be the length of the water column,then:

Water rises up to a height $h$ in a capillary tube of a certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now,the water will rise to a height of:

$A$ glass capillary tube of inner diameter $0.28 \,mm$ is lowered vertically into water in a vessel. The pressure to be applied on the water in the capillary tube so that the water level in the tube is the same as that in the vessel is ............ $\times 10^3 \,N/m^2$ (surface tension of water $= 0.07 \,N/m$ and atmospheric pressure $= 10^5 \,N/m^2$).

$A$ capillary tube of radius $R$ is immersed in water and water rises in it to a height $H$. The mass of water in the capillary tube is $M$. If the radius of the tube is halved,the mass of water that will rise in the capillary tube will now be