The correct statement regarding SO_2 molecule | vedclass

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Question

(D) The $SO_2$ molecule has a bent geometry with the central sulfur atom bonded to two oxygen atoms.Sulfur has an electronic configuration of $[Ne] 3s

Vedclass · Accepted Answer

one $p\pi - p\pi$ and one $p\pi - d\pi$ bond

Vedclass · Answer

(D) The $SO_2$ molecule has a bent geometry with the central sulfur atom bonded to two oxygen atoms.Sulfur has an electronic configuration of $[Ne] 3s^2 3p^4$.In the excited state,sulfur forms two $\sigma$ bonds and two $\pi$ bonds.One $\pi$ bond is formed by the overlap of $p$-orbitals of sulfur and oxygen ($p\pi - p\pi$ bond),and the other $\pi$ bond is formed by the overlap of the $d$-orbital of sulfur and the $p$-orbital of oxygen ($p\pi - d\pi$ bond).Therefore,the molecule contains one $p\pi - p\pi$ bond and one $p\pi - d\pi$ bond.

List-$I$	List-$II$
$A. Li_2$	$i. 3$
$B. N_2$	$ii. 1.5$
$C. Be_2$	$iii. 1.0$
$D. O_2$	$iv. 0$
	$v. 2$

The correct statement regarding $SO_2$ molecule is

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Match the molecules in List-$I$ with their respective bond orders in List-$II$.
List-$I$ List-$II$
$A. Li_2$ $i. 3$
$B. N_2$ $ii. 1.5$
$C. Be_2$ $iii. 1.0$
$D. O_2$ $iv. 0$
$v. 2$

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