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(C) The energy of an emitted photon is given by $\Delta E = E_{initial} - E_{final}$.Emission occurs when an electron transitions from a higher energy

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$III$

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(C) The energy of an emitted photon is given by $\Delta E = E_{initial} - E_{final}$.Emission occurs when an electron transitions from a higher energy level to a lower energy level, which corresponds to downward arrows in the diagram.Transitions $II$, $III$, and $IV$ represent emission.Transition $II$ is from $n=4$ to $n=3$.Transition $III$ is from $n=2$ to $n=1$.Transition $IV$ is from $n=4$ to $n=2$.The energy difference $\Delta E$ is proportional to the gap between the energy levels.Comparing the gaps, the gap between $n=2$ and $n=1$ (transition $III$) is significantly larger than the gaps for $II$ and $IV$.Therefore, transition $III$ releases the most energy.

The diagram shows the energy levels for an electron in a certain atom. Which transition shown represents the emission of a photon with the most energy?

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