The diameter of a cylinder is measured using a vernier callipers with no zero error. It is found that the zero of the vernier scale lies between $5.10 \ cm$ and $5.15 \ cm$ of the main scale. The vernier scale has $50$ divisions equivalent to $2.45 \ cm$. The $24^{\text{th}}$ division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is: (in $cm$)
- A$5.112$
- B$5.124$
- C$5.136$
- D$5.148$
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Similar Questions
$A$ vernier callipers has $20$ divisions on the vernier scale, which coincide with $19$ divisions on the main scale. The least count of the instrument is $0.1 \,mm$. One main scale division is equal to $...$ $mm$.
Match the instruments in Column-$I$ with their respective least counts in Column-$II$.
Column-$I$ Column-$II$ $(1)$ Traveling Microscope $(a)$ $0.01\,cm$ $(2)$ Screw Gauge $(b)$ $0.001\,cm$ $(c)$ $0.0001\,cm$
| Column-$I$ | Column-$II$ |
| $(1)$ Traveling Microscope | $(a)$ $0.01\,cm$ |
| $(2)$ Screw Gauge | $(b)$ $0.001\,cm$ |
| $(c)$ $0.0001\,cm$ |
Medium
View SolutionLength of $9 \ MSD$ of a vernier caliper are equal to $10 \ VSD$ and $1 \ MSD = 1 \ mm$. For measuring the length of a rod,the reading on the main scale is $6.4 \ cm$ and the $8^{th}$ division on the vernier scale is in line with a marking on the main scale. If there is no zero error,find the length of the rod: (in $cm$)
Medium
View SolutionThe length of a cylinder measured by a Vernier caliper is given by the following observations: $3.29 \, cm, 3.28 \, cm, 3.29 \, cm, 3.31 \, cm, 3.28 \, cm, 3.27 \, cm, 3.29 \, cm, 3.30 \, cm$. The most accurate length of the cylinder is ........ $cm$.
Easy
View SolutionIn an experiment,the angles are required to be measured using an instrument in which $29$ divisions of the main scale exactly coincide with the $30$ divisions of the vernier scale. If the smallest division of the main scale is half a degree $(=0.5^{\circ})$,then the least count of the instrument is
DifficultTS EAMCET 2020
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