The dimensions of the ratio of magnetic flux | vedclass

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(A) Magnetic flux,$\phi = B A$ $(1)$,where $B$ is the magnetic field and $A$ is the area.Also,$B = \mu H$ $(2)$,where $\mu$ is permeability and $H$ is

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$[M^{0} L^{1} T^{0} A^{1}]$

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(A) Magnetic flux,$\phi = B A$ $(1)$,where $B$ is the magnetic field and $A$ is the area.Also,$B = \mu H$ $(2)$,where $\mu$ is permeability and $H$ is magnetic field intensity.Substituting Eq. $(2)$ into Eq. $(1)$,we get $\phi = (\mu H) A$.Rearranging,we find the ratio $\frac{\phi}{\mu} = H A$.The dimensions of area $A$ are $[L^{2}]$.The magnetic field intensity $H$ is defined as $\frac{	ext{Number of turns} 	imes 	ext{Current}}{	ext{Length}}$,so its dimensions are $[L^{-1} A]$.Therefore,the dimensions of $\frac{\phi}{\mu} = [L^{-1} A] 	imes [L^{2}] = [L^{1} A]$.In terms of $M, L, T, A$,this is $[M^{0} L^{1} T^{0} A^{1}]$.

The dimensions of the ratio of magnetic flux $(\phi)$ and permeability $(\mu)$ are

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