The dipole moment of each molecule of a param | vedclass

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(A) The intensity of magnetization $I$ is defined as the net magnetic dipole moment per unit volume.For maximum magnetization,all molecular dipoles mu

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$3 	imes 10^3 \, A/m$

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(A) The intensity of magnetization $I$ is defined as the net magnetic dipole moment per unit volume.For maximum magnetization,all molecular dipoles must be aligned in the same direction.Given:Dipole moment of each molecule,$\mu = 1.5 	imes 10^{-23} \, A \cdot m^2$Number of molecules per unit volume,$n = \frac{N}{V} = 2 	imes 10^{26} \, m^{-3}$The formula for intensity of magnetization is $I = n 	imes \mu$.Substituting the values:$I = (2 	imes 10^{26} \, m^{-3}) 	imes (1.5 	imes 10^{-23} \, A \cdot m^2)$$I = 3 	imes 10^3 \, A/m$.Thus,the maximum possible intensity of magnetization is $3 	imes 10^3 \, A/m$.

The dipole moment of each molecule of a paramagnetic gas is $1.5 \times 10^{-23} \, A \cdot m^2$. The temperature of the gas is $27 \, ^\circ C$ and the number of molecules per unit volume is $2 \times 10^{26} \, m^{-3}$. The maximum possible intensity of magnetization in the gas will be:

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