The relation between $\mu$ and $H$ for a specimen of iron is $\mu = [\frac{0.4}{H} + 12 \times 10^{-4}] \ H m^{-1}$. The value of $H$ which produces a flux density of $1 \ T$ will be ($\mu =$ magnetic permeability,$H =$ magnetic intensity).

The magnetic moment of a sample of $2 \text{ g}$ is $8 \times 10^{-7} \text{ Am}^2$. If its density is $4 \text{ g/cm}^3$,then the magnetization of the sample in $\text{Am}^{-1}$ is:

The correct relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_0)$ and susceptibility $(\chi)$ is

The magnetic susceptibility of any paramagnetic material changes with absolute temperature $T$ as

What are the dimensions of $\chi$,the magnetic susceptibility? Consider an $H$-atom. Guess an expression for $\chi$,up to a constant,by constructing a quantity of dimensions of $\chi$ out of parameters of the atom: $e, m, v, R$ and $\mu_0$. Here,$m$ is the electronic mass,$v$ is electronic velocity,$R$ is Bohr radius. Estimate the number so obtained and compare with the value of $|\chi| \approx 10^{-5}$ for many solid materials.

$ \chi_{1} $ and $ \chi_{2} $ are the magnetic susceptibilities of a paramagnetic material at temperatures $ T_{1} \ K $ and $ T_{2} \ K $ respectively. Then: