The end product of the $(4n + 1)$ radioactive disintegration series is:
- A$_{83}Bi^{209}$
- B$_{84}Po^{210}$
- C$_{82}Pb^{208}$
- D$_{82}Pb^{207}$
Explore More
Similar Questions
Which of the following can be used for carrying out a nuclear fission reaction?
Medium
View SolutionWhich of the following isotopes is likely to be most stable?
Medium
View SolutionWhat is $X$ in the following nuclear reaction?
$_{7}N^{14} + _{1}H^{1} \xrightarrow{} _{8}O^{15} + X$
$_{7}N^{14} + _{1}H^{1} \xrightarrow{} _{8}O^{15} + X$
DifficultAIIMS 1983
View SolutionThe huge amount of energy which is released during atomic fission is due to
Medium
View SolutionAssertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.
MediumAIIMS 2004
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo