The energy liberated per nuclear fission is $200 \; MeV$. If $10^{20}$ fissions occur per second,the amount of power produced will be:

  • A
    $32 \times 10^8 \; W$
  • B
    $16 \times 10^8 \; W$
  • C
    $5 \times 10^{11} \; W$
  • D
    $2 \times 10^{22} \; W$

Explore More

Similar Questions

Which reaction is not part of the proton-proton cycle?

Nuclear fission experiments show that neutrons split uranium nuclei into two fragments of about the same size. This process is accompanied by the emission of several:

The energy released by the fission of one uranium atom is $200 MeV$. The number of fissions per second required to produce $3.2 W$ of power is (Take $1 eV = 1.6 \times 10^{-19} J$).

The operation of a nuclear reactor is said to be critical when the value of the neutron multiplication factor $K$ is:

Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo