Class 11MathematicsPair of straight linesBisectors of the angle between the lines, Point of intersection of the lines
DifficultThe equation of a pair of lines $y=px$ and $y=qx$ can be written as $(y-px)(y-qx)=0$. Then the equation of the pair of angle bisectors of the lines $x^2-4xy-5y^2=0$ is
- A$x^2-3xy+y^2=0$
- B$x^2+4xy-y^2=0$
- C$x^2-3xy-y^2=0$
- D$x^2+3xy-y^2=0$
Explore More
Similar Questions
The condition for the general quadratic equation $f(x, y) = ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0$ to represent coincident lines is:
Difficult
View SolutionIf pairs of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 q x y-y^2=0$ are such that each pair bisects the angle between the other pair,then:
If a pair of lines $x^{2}-2 p x y-y^{2}=0$ and $x^{2}-2 q x y-y^{2}=0$ are such that each pair bisects the angle between the other pair,then
If $y = mx$ is one of the bisectors of the angle between the lines $ax^2 - 2hxy + by^2 = 0$,then
Difficult
View SolutionIf the lines $x^2+2xy-35y^2-4x+44y-12=0$ and $5x+ky-8=0$ are concurrent,then $k$ equals
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo