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Question

(A) The equation of the pair of straight lines passing through the origin and the intersection points of a curve $S = 0$ and a line $L = 0$ is given b

Vedclass · Accepted Answer

$x^2 + y^2 = (y - x)^2$

Vedclass · Answer

(A) The equation of the pair of straight lines passing through the origin and the intersection points of a curve $S = 0$ and a line $L = 0$ is given by homogenizing the curve equation using the line equation.Given curve: $x^2 + y^2 = 4$Given line: $y - x = 2$,which implies $\frac{y - x}{2} = 1$.Substituting this into the curve equation to homogenize it:$x^2 + y^2 = 4 	imes (1)^2$$x^2 + y^2 = 4 	imes \left( \frac{y - x}{2} ight)^2$$x^2 + y^2 = 4 	imes \frac{(y - x)^2}{4}$$x^2 + y^2 = (y - x)^2$.

The equation of the pair of straight lines joining the origin to the points of intersection of the curve $x^2 + y^2 = 4$ and the line $y - x = 2$ is

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