The equation of the line joining the points $(-3, 4, 11)$ and $(1, -2, 7)$ is

  • A
    $\frac{x+3}{2} = \frac{y-4}{3} = \frac{z-11}{4}$
  • B
    $\frac{x+3}{-2} = \frac{y-4}{3} = \frac{z-11}{2}$
  • C
    $\frac{x+3}{-2} = \frac{y+4}{3} = \frac{z+11}{4}$
  • D
    $\frac{x+3}{2} = \frac{y+4}{-3} = \frac{z+11}{2}$

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Statement $1:$ The shortest distance between the lines $\frac{x}{2} = \frac{y}{-1} = \frac{z}{2}$ and $\frac{x-1}{4} = \frac{y-1}{-2} = \frac{z-1}{4}$ is $\sqrt{2}$.
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Let a line $L$ be perpendicular to both the lines $L_1: \frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}$ and $L_2: \frac{x-2}{1} = \frac{y-4}{4} = \frac{z-6}{7}$. If $\theta$ is the acute angle between the lines $L$ and $L_3: \frac{x-7}{2} = \frac{y-7}{1} = \frac{z}{2}$, then $\tan \theta$ is equal to:

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