The equation of the tangent at P(-4, -4) on t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the curve equation is $x^{2} = -4y$. Differentiating both sides with respect to $x$,we get $2x = -4 \frac{dy}{dx}$. Thus,$\frac{dy}{dx} = -\

Vedclass · Accepted Answer

$2x - y + 4 = 0$

Vedclass · Answer

(B) Given the curve equation is $x^{2} = -4y$. Differentiating both sides with respect to $x$,we get $2x = -4 \frac{dy}{dx}$. Thus,$\frac{dy}{dx} = -\frac{x}{2}$. The slope of the tangent at point $P(-4, -4)$ is $m = -\frac{-4}{2} = 2$. The equation of the tangent line passing through $P(x_1, y_1) = (-4, -4)$ with slope $m = 2$ is given by $y - y_1 = m(x - x_1)$. Substituting the values,we get $y - (-4) = 2(x - (-4))$. $y + 4 = 2(x + 4)$. $y + 4 = 2x + 8$. $2x - y + 4 = 0$. Therefore,the correct option is $B$.

The equation of the tangent at $P(-4, -4)$ on the curve $x^{2} = -4y$ is

Similar Questions

The intercepts of the focal chord (which is a part of the latus rectum) to the parabola $y^{2}=4ax$ are $b$ and $k$. Then $k$ is equal to:

What is the eccentricity of a parabola?

If one end of a focal chord $AB$ of the parabola $y^{2}=8x$ is at $A\left(\frac{1}{2},-2\right)$,then the equation of the tangent to it at $B$ is:

The area of the triangle formed inside the parabola $y^2 = 4x$ whose vertices have ordinates $1, 2,$ and $4$ is:

If $x + by + c = 0$ is a normal to the parabola $y^2 = 12x$,then the complete set of all values of $c$ is -

Vedclass Test Series

Exam Paper Generator

Online Exam Module