The equations of the lines represented by the equation $ax^2 + (a + b)xy + by^2 + x + y = 0$ are
- A$ax + by + 1 = 0$,$x + y = 0$
- B$ax + by - 1 = 0$,$x + y = 0$
- C$ax + by + 1 = 0$,$x - y = 0$
- DNone of these
Explore More
Similar Questions
If the slope of one of the two lines represented by $\frac{x^2}{a} + \frac{2xy}{h} + \frac{y^2}{b} = 0$ is twice that of the other,then $ab : h^2 = $
Two of the lines represented by the equation $a y^4+b x y^3+c x^2 y^2+d x^3 y+e x^4=0$ will be perpendicular,then
DifficultAP EAMCET 2021
View SolutionThe equation of the pair of straight lines passing through the point $(1,1)$ and perpendicular to the pair of straight lines $3x^2-8xy+5y^2=0$ is
The combined equation of two lines $L$ and $L_1$ is $2x^2+axy+3y^2=0$ and the combined equation of two lines $L$ and $L_2$ is $2x^2+bxy-3y^2=0$. If $L_1$ and $L_2$ are perpendicular,then $a^2+b^2=$
If the sum of the slopes of the lines given by $x^2-4pxy+8y^2=0$ is three times their product,then $p=\ldots$
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo