The equations of the perpendicular bisectors of the sides $AB$ and $AC$ of a $\triangle ABC$ are $x-y+5=0$ and $x+2y+5=0$,respectively. If $A$ is $(1, -2)$,then the equation of the straight line $BC$ is

  • A
    $14x+23y-40=0$
  • B
    $12x+17y-28=0$
  • C
    $14x-29y-30=0$
  • D
    $7x-12y+15=0$

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