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(D) From the circuit diagram,we can observe that the three capacitors in the bottom branch are connected in series. The equivalent capacitance of thes

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$\frac{4C}{3}$

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(D) From the circuit diagram,we can observe that the three capacitors in the bottom branch are connected in series. The equivalent capacitance of these three capacitors is given by $\frac{1}{C_s} = \frac{1}{C} + \frac{1}{C} + \frac{1}{C} = \frac{3}{C}$,which implies $C_s = \frac{C}{3}$.This equivalent capacitor $C_s$ is connected in parallel with the top capacitor $C$. Therefore,the total equivalent capacitance between points $A$ and $B$ is $C_{eq} = C_s + C = \frac{C}{3} + C = \frac{4C}{3}$.

The equivalent capacitance between $A$ and $B$ is

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