व्यंजक frac{tan left( frac{3pi}{2} - alpha ri | vedclass

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(A) त्रिकोणमितीय सर्वसमिकाओं का उपयोग करते हुए:$	an \left( \frac{3\pi}{2} - \alpha ight) = \cot \alpha$$\cos \left( \frac{3\pi}{2} - \alpha ight)

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) त्रिकोणमितीय सर्वसमिकाओं का उपयोग करते हुए:$	an \left( \frac{3\pi}{2} - \alpha ight) = \cot \alpha$$\cos \left( \frac{3\pi}{2} - \alpha ight) = -\sin \alpha$$\cos (2\pi - \alpha ) = \cos \alpha$$\cos \left( \alpha - \frac{\pi}{2} ight) = \sin \alpha$$\sin (\pi - \alpha ) = \sin \alpha$$\cos (\pi + \alpha ) = -\cos \alpha$$\sin \left( \alpha - \frac{\pi}{2} ight) = -\cos \alpha$इन मानों को व्यंजक में रखने पर:$= \frac{(\cot \alpha )(-\sin \alpha )}{\cos \alpha } + (\sin \alpha )(\sin \alpha ) + (-\cos \alpha )(-\cos \alpha )$$= \frac{(\frac{\cos \alpha }{\sin \alpha })(-\sin \alpha )}{\cos \alpha } + \sin^2 \alpha + \cos^2 \alpha$$= -1 + 1 = 0$

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