The factorisation of 4 x^{2}+8 x+3 is | vedclass

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Question

(A) To factorise the quadratic expression $4 x^{2}+8 x+3$,we use the splitting the middle term method.We need to find two numbers whose product is $4

Vedclass · Accepted Answer

$(2 x+1)(2 x+3)$

Vedclass · Answer

(A) To factorise the quadratic expression $4 x^{2}+8 x+3$,we use the splitting the middle term method.We need to find two numbers whose product is $4 	imes 3 = 12$ and whose sum is $8$.These two numbers are $6$ and $2$,since $6 	imes 2 = 12$ and $6 + 2 = 8$.Now,rewrite the middle term $8x$ as $6x + 2x$:$4 x^{2}+6 x+2 x+3$Group the terms:$(4 x^{2}+6 x) + (2 x+3)$Factor out the common terms from each group:$2 x(2 x+3) + 1(2 x+3)$Finally,factor out the common binomial $(2 x+3)$:$(2 x+3)(2 x+1)$Thus,the correct option is $A$.

The factorisation of $4 x^{2}+8 x+3$ is

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