The feasible region for a $LPP$ is shown in the figure. Find the minimum value of $Z=11x+7y$.

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(A) The lines $x+y=5$ and $x+3y=9$ intersect at $(3,2)$. From the figure,the feasible region is bounded with corner points $C(0,3)$,$A(3,2)$,and $B(0,5)$.
We evaluate the objective function $Z=11x+7y$ at each corner point:
Corner Point Value of $Z=11x+7y$
$C(0,3)$ $11(0)+7(3) = 21$
$A(3,2)$ $11(3)+7(2) = 33+14 = 47$
$B(0,5)$ $11(0)+7(5) = 35$

Comparing the values of $Z$,the minimum value is $21$ at the point $(0,3)$.

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Maximize the function $Z = 11x + 7y$,subject to the constraints:
$x \leq 3, y \leq 2, x \geq 0, y \geq 0$

Determine graphically the minimum value of the objective function
$Z = -50x + 20y$ .....$(1)$
subject to the constraints:
${2x - y \geqslant -5}$ .....$(2)$
${3x + y \geqslant 3}$ .....$(3)$
${2x - 3y \leqslant 12}$ .....$(4)$
${x \geqslant 0, y \geqslant 0}$ .....$(5)$

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