The following table gives the production yield per hectare of wheat of $100$ farms of a village.
Production yield (in kg/ha)Number of farms
$50-55$$2$
$55-60$$8$
$60-65$$12$
$65-70$$24$
$70-75$$38$
$75-80$$16$

Change the distribution to a 'more than type' distribution,and draw its ogive.

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(N/A) The cumulative frequency distribution of 'more than type' can be obtained as follows:
Production yield (lower class limits)Cumulative frequency
More than or equal to $50$$100$
More than or equal to $55$$100 - 2 = 98$
More than or equal to $60$$98 - 8 = 90$
More than or equal to $65$$90 - 12 = 78$
More than or equal to $70$$78 - 24 = 54$
More than or equal to $75$$54 - 38 = 16$

By plotting the points $(50, 100), (55, 98), (60, 90), (65, 78), (70, 54), (75, 16)$ on a graph paper,taking the lower class limits on the $x$-axis and their respective cumulative frequencies on the $y$-axis,we obtain the 'more than type' ogive.

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Similar Questions

The median class of the following frequency distribution is ...........
Class$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$
Frequency$4$$5$$9$$10$$14$$8$

Total frequency $n = 50$.

The distribution below gives the weights of $30$ students of a class. Find the median weight of the students.
Weight (in kg)$40-45$$45-50$$50-55$$55-60$$60-65$$65-70$$70-75$
Number of students$2$$3$$8$$6$$6$$3$$2$

Find the median of the following frequency distribution:
Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$
Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$

Find the unknown entries $a, b, c, d, e, f$ in the following distribution of heights of students in a class:
Height (in $cm$) Frequency Cumulative frequency
$150-155$ $12$ $a$
$155-160$ $b$ $25$
$160-165$ $10$ $c$
$165-170$ $d$ $43$
$170-175$ $e$ $48$
$175-180$ $2$ $f$
Total $50$ -

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times c$ for the median,$cf = \ldots \ldots \ldots$

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