The formula to find the mean of a grouped data by the direct method is .........
- A$\bar{x}=\frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$
- B$\bar{x}=\frac{\Sigma x_{i}}{\Sigma f_{i}}$
- C$\bar{x}=\frac{\Sigma f_{i} x_{i}}{n}$
- D$\bar{x}=\frac{\Sigma f_{i} x_{i}}{n} \times c$
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Similar Questions
Find the mean of the following frequency distribution:
Class
$21-25$
$26-30$
$31-35$
$36-40$
$41-45$
$46-50$
$51-55$
Frequency
$18$
$32$
$30$
$40$
$25$
$15$
$40$
(in $.675$)
| Class | $21-25$ | $26-30$ | $31-35$ | $36-40$ | $41-45$ | $46-50$ | $51-55$ |
| Frequency | $18$ | $32$ | $30$ | $40$ | $25$ | $15$ | $40$ |
Easy
View SolutionCalculate the mean of the frequency distribution of the marks scored by $100$ students in a mathematics test:
Marks $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ No. of students $20$ $10$ $20$ $30$ $20$
| Marks | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
| No. of students | $20$ | $10$ | $20$ | $30$ | $20$ |
Medium
View SolutionThe mean of the following frequency distribution is $65$ and the total frequency is $100$. Find the missing frequencies $f_{1}$ and $f_{2}$.
Class $15-35$ $35-55$ $55-75$ $75-95$ $95-115$ Frequency $17$ $f_1$ $32$ $f_2$ $19$
| Class | $15-35$ | $35-55$ | $55-75$ | $75-95$ | $95-115$ |
| Frequency | $17$ | $f_1$ | $32$ | $f_2$ | $19$ |
Medium
View SolutionIn the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$ for the mean,$u_{i} = \ldots \ldots \ldots$
Easy
View SolutionFor a given frequency distribution,$\bar{x}=54.3, \Sigma f_{i} u_{i}=2, n=25$ and $c=10$. Then the assumed mean $A = \dots$
Medium
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