The ground state energy of a hydrogen atom is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total energy $(E)$ of an electron in a hydrogen atom is the sum of its kinetic energy $(K)$ and potential energy $(U)$.For a hydrogen atom,the

Vedclass · Accepted Answer

-$27.2$

Vedclass · Answer

(A) The total energy $(E)$ of an electron in a hydrogen atom is the sum of its kinetic energy $(K)$ and potential energy $(U)$.For a hydrogen atom,the relationship between total energy $(E)$,kinetic energy $(K)$,and potential energy $(U)$ is given by $E = -K = U/2$.Given the ground state energy $E = -13.6 \ eV$.Therefore,the potential energy $U = 2 	imes E$.$U = 2 	imes (-13.6 \ eV) = -27.2 \ eV$.Thus,the correct option is $A$.

The ground state energy of a hydrogen atom is $-13.6 \ eV$. In this state,the potential energy is . . . . . . $eV$.

Similar Questions

Radius of the first orbit of the electron in a hydrogen atom is $0.53 \; \mathring{A}$. So,the radius of the third orbit will be ........... $\mathring{A}$.

The de Broglie wavelength of an electron in the first orbit of Bohr's model is . . . . . . .

The radius of the Bohr orbit in the ground state of a hydrogen atom is $0.5 \ \mathring{A}$. The radius of the orbit of the electron in the third excited state of $He^+$ will be ...... $\mathring{A}$.

The time of revolution of an electron around a nucleus of charge $Ze$ in the $n^{th}$ Bohr orbit is directly proportional to

If $E$ and $L$ denote the magnitudes of total energy and of angular momentum of an electron in a Bohr orbit,then the true relation between them is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module