The hybridization involved in the complex $[Ni(CN)_4]^{2-}$ is (Atomic number of $Ni = 28$):

  • A
    $sp^3$
  • B
    $d^2sp^2$
  • C
    $d^2sp^3$
  • D
    $dsp^2$

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Observe the following complexes: $[Mn(CN)_6]^{3-}, [Fe(CN)_6]^{3-}, [Co(C_2O_4)_3]^{3-}, [MnCl_6]^{3-}, [Fe(CN)_6]^{4-}, [CoF_6]^{3-}$. From the above,the number of inner orbital complexes with paramagnetic nature is

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State the limitations of valence bond theory.

The magnetic moment for two complexes of empirical formula $Ni(NH_3)_4(NO_3)_2 \cdot 2H_2O$ is $0$ and $2.84 \ BM$ respectively. The second complex is not a neutral complex. The correct formula and geometry of the first complex is:

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Aluminium chloride in acidified aqueous solution forms a complex $A$,in which hybridisation of $Al$ is $B$. What are $A$ and $B$,respectively?

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