The integral value of k for which x^2 - 2(4k | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a quadratic expression $ax^2 + bx + c > 0$ to be true for all $x \in R$,the conditions are $a > 0$ and the discriminant $D < 0$.Here,$a = 1$,w

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) For a quadratic expression $ax^2 + bx + c > 0$ to be true for all $x \in R$,the conditions are $a > 0$ and the discriminant $D Here,$a = 1$,which is $> 0$.The discriminant $D = b^2 - 4ac $D = [-2(4k - 1)]^2 - 4(1)(15k^2 - 2k - 7) $4(16k^2 - 8k + 1) - 4(15k^2 - 2k - 7) Dividing by $4$,we get $16k^2 - 8k + 1 - 15k^2 + 2k + 7 $k^2 - 6k + 8 $(k - 2)(k - 4) This inequality holds for $2 The only integer value of $k$ in this interval is $k = 3$.

The integral value of $k$ for which $x^2 - 2(4k - 1)x + 15k^2 - 2k - 7 > 0$ for all $x \in R$ is

Similar Questions

The set of values of $x$ for which the inequalities $x^2-3x-10 < 0$ and $10x-x^2-16 > 0$ hold simultaneously is:

If $a < 0$,then the inequality $ax^2 - 2x + 4 > 0$ has the solution represented by:

The set $\{x \in R: 4+11x-3x^2>0\}$ is the interval

The solution set contained in $R^{+}$ of the inequation $3^x + 3^{1-x} - 4 < 0$ is

The integer $k$,for which the inequality $x^{2}-2(3k-1)x+8k^{2}-7>0$ is valid for every $x \in \mathbb{R}$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module