The jogging track in a sports complex is 726 | vedclass

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(B) The circumference of the track is $726 \, m = 0.726 \, km$.Since they are walking in opposite directions,their relative speed is the sum of their

Vedclass · Accepted Answer

$5.28$

Vedclass · Answer

(B) The circumference of the track is $726 \, m = 0.726 \, km$.Since they are walking in opposite directions,their relative speed is the sum of their individual speeds.Relative speed $= 4.5 \, km/h + 3.75 \, km/h = 8.25 \, km/h$.Time taken to meet for the first time $= \frac{	ext{Distance}}{	ext{Relative speed}} = \frac{0.726 \, km}{8.25 \, km/h}$.Time in hours $= \frac{0.726}{8.25} \, h$.To convert this into minutes,multiply by $60$:Time in minutes $= \left( \frac{0.726}{8.25} ight) 	imes 60 \, min = 0.088 	imes 60 \, min = 5.28 \, min$.

The jogging track in a sports complex is $726 \, m$ in circumference. Deepak and his wife start from the same point and walk in opposite directions at $4.5 \, km/h$ and $3.75 \, km/h$ respectively. They will meet for the first time in (in $min$):

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