The length of a cylinder is measured with a m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The volume of a cylinder is given by $V = \pi r^2 l$.The relative error in volume is given by $\frac{\Delta V}{V} = 2 \frac{\Delta r}{r} + \frac{\

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The volume of a cylinder is given by $V = \pi r^2 l$.The relative error in volume is given by $\frac{\Delta V}{V} = 2 \frac{\Delta r}{r} + \frac{\Delta l}{l}$.Given:Length $l = 5.0 \, cm$,$\Delta l = 0.1 \, cm$.Radius $r = 2.0 \, cm$,$\Delta r = 0.01 \, cm$ (since the least count of the vernier caliper applies to the diameter,the error in radius is the same as the least count of the instrument,$0.01 \, cm$).Percentage error in volume = $\left( 2 \frac{\Delta r}{r} + \frac{\Delta l}{l} ight) 	imes 100$.$= \left( 2 	imes \frac{0.01}{2.0} 	imes 100 + \frac{0.1}{5.0} 	imes 100 ight) \%$.$= (1 + 2) \% = 3 \%$.

List-$I$	List-$II$
$(i)$ Curie	$(A)$ $MLT^{-2}$
$(ii)$ Light year	$(B)$ $M$
$(iii)$ Dielectric strength	$(C)$ Dimensionless
$(iv)$ Atomic weight	$(D)$ $T$
$(v)$ Decibel	$(E)$ $ML^2T^{-2}$
	$(F)$ $MT^{-3}$
	$(G)$ $T^{-1}$
	$(H)$ $L$
	$(I)$ $MLT^{-3}I^{-1}$
	$(J)$ $LT^{-1}$

Similar Questions

It is estimated that each $cm^2$ of Earth receives about $2 \text{ calorie}$ of heat energy per minute from the Sun. This is called the solar constant. The value of the solar constant in $S.I.$ units is:

Which of the following pairs of physical quantities does not have the same dimensional formula?

Which physical quantities have the same dimension?

$A$ scalar quantity is one that

Vedclass Test Series

Exam Paper Generator

Online Exam Module