The length of a simple pendulum is increased | vedclass

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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$.From this relation,we can see that $T \propto \sqrt{l}$

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Increase by $0.5\%$

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(B) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g}}$.From this relation,we can see that $T \propto \sqrt{l}$.Taking the logarithmic derivative,we get $\frac{\Delta T}{T} = \frac{1}{2} \frac{\Delta l}{l}$.Given that the length is increased by $1\%$,we have $\frac{\Delta l}{l} = 1\%$.Substituting this value,we get $\frac{\Delta T}{T} = \frac{1}{2} 	imes 1\% = 0.5\%$.Therefore,the time period will increase by $0.5\%$.

The length of a simple pendulum is increased by $1\%$. Its time period will

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