The list of numbers -10, -6, -2, 2, ldots is | vedclass

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Question

(A) The given sequence is $-10, -6, -2, 2, \ldots$Here,the first term $a_1 = -10$,the second term $a_2 = -6$,the third term $a_3 = -2$,and the fourth

Vedclass · Accepted Answer

an $AP$ with $d = 4$

Vedclass · Answer

(A) The given sequence is $-10, -6, -2, 2, \ldots$Here,the first term $a_1 = -10$,the second term $a_2 = -6$,the third term $a_3 = -2$,and the fourth term $a_4 = 2$.To check if the sequence is an $AP$,we calculate the common difference $d$ between consecutive terms:$d_1 = a_2 - a_1 = -6 - (-10) = -6 + 10 = 4$$d_2 = a_3 - a_2 = -2 - (-6) = -2 + 6 = 4$$d_3 = a_4 - a_3 = 2 - (-2) = 2 + 2 = 4$Since the difference between consecutive terms is constant $(d = 4)$,the given list of numbers forms an $AP$ with a common difference $d = 4$.

The list of numbers $-10, -6, -2, 2, \ldots$ is

Similar Questions

For the following $APs,$ write the first term and the common difference: $0.6, 1.7, 2.8, 3.9, \ldots$

Does the sequence $-2, 2, -2, 2, -2, \ldots$ form an $AP$? If it forms an $AP$,write the next two terms.

If $2x$,$x+10$,and $3x+2$ are three consecutive terms of an $A.P.$,find the value of $x$.

Do $4, 10, 16, 22, \ldots$ form an $AP$? If they form an $AP,$ write the next two terms.

Which of the following form an $AP$? Justify your answer.
$(i)$ $-1, -1, -1, -1, \ldots$
$(ii)$ $0, 2, 0, 2, \ldots$
$(iii)$ $1, 1, 2, 2, 3, 3, \ldots$

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