(A) Given that the magnitudes are $|\vec A| = 3$, $|\vec B| = 4$, and $|\vec C| = 5$.Since $\vec A + \vec B = \vec C$, we can check if the magnitudes

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(A) Given that the magnitudes are $|\vec A| = 3$, $|\vec B| = 4$, and $|\vec C| = 5$.Since $\vec A + \vec B = \vec C$, we can check if the magnitudes satisfy the Pythagorean theorem: $|\vec A|^2 + |\vec B|^2 = 3^2 + 4^2 = 9 + 16 = 25 = 5^2 = |\vec C|^2$.Since $|\vec A|^2 + |\vec B|^2 = |\vec C|^2$, the vectors $\vec A$ and $\vec B$ must be perpendicular to each other.Therefore, the angle between $\vec A$ and $\vec B$ is $\frac{\pi}{2}$.

Class 11 Physics 1 Motion in a Plane: Vectors Addition and Subtraction of Vectors

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The magnitudes of vectors $\vec A, \vec B$ and $\vec C$ are $3, 4$ and $5$ units respectively. If $\vec A + \vec B = \vec C$, the angle between $\vec A$ and $\vec B$ is

AIPMT 1988 All AIPMT

A
$\frac{\pi}{2}$
B
$\cos^{-1}(0.6)$
C
$\tan^{-1}\left(\frac{7}{5}\right)$
D
$\frac{\pi}{4}$

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1 Motion in a Plane: Vectors

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Addition and Subtraction of Vectors

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AIPMT 1988 Paper All AIPMT years →

Given that $A_1+A_2=5 A_3$ and $A_1-A_2=3 A_3$, where $A_3=2 \hat{i}+4 \hat{j}$, find the value of $\frac{|A_1|}{|A_2|}$.

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The magnitude of the sum of the two vectors $\vec{A}$ and $\vec{B}$ is equal to the magnitude of the difference of the two vectors $\vec{A}$ and $\vec{B}$. The angle between $\vec{A}$ and $\vec{B}$ is: (in $^{\circ}$)

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The resultant of two vectors $\vec{A}$ and $\vec{B}$ is $\vec{C}$. If the magnitude of $\vec{B}$ is doubled,the new resultant vector becomes perpendicular to $\vec{A}$. Then the magnitude of $\vec{C}$ is

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The magnitudes of vectors $\vec A, \vec B$ and $\vec C$ are $3, 4$ and $5$ units respectively. If $\vec A + \vec B = \vec C$, the angle between $\vec A$ and $\vec B$ is

Similar Questions

Given that $A_1+A_2=5 A_3$ and $A_1-A_2=3 A_3$, where $A_3=2 \hat{i}+4 \hat{j}$, find the value of $\frac{|A_1|}{|A_2|}$.

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