The major product formed in the following tra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction proceeds in two steps: $1$. Reduction of cyclobutyl methyl ketone with $NaBH_4/MeOH$ yields $1-cyclobutyl-1-ethanol$. $2$. Treatment

Vedclass · Accepted Answer

$1-$bromo$-1-$methylcyclopentane

Vedclass · Answer

(B) The reaction proceeds in two steps: $1$. Reduction of cyclobutyl methyl ketone with $NaBH_4/MeOH$ yields $1-cyclobutyl-1-ethanol$. $2$. Treatment with $HBr$ leads to the protonation of the alcohol,followed by the loss of water to form a secondary carbocation. $3$. This secondary carbocation undergoes ring expansion to form a more stable cyclopentyl carbocation. $4$. $A$ $1,2-hydride$ shift occurs to form a more stable tertiary carbocation. $5$. Finally,the nucleophilic attack by $Br^-$ yields $1-bromo-1-methylcyclopentane$ as the major product.

The major product formed in the following transformation is most likely to be

Similar Questions

In which of the following reactions will hydrogen gas not be evolved?

$A$ compound $X$ with the molecular formula $C_3H_8O$ yields a compound with the formula $C_3H_6O$ upon oxidation. To which of the following classes of compounds could $X$ belong?

Of the following alcohols,the one that would react fastest with conc. $HCl$ and anhydrous $ZnCl_{2}$ is,

$A$ reaction between $CH_3MgBr$ (methyl magnesium bromide) and $C_2H_5OH$ (ethyl alcohol) gives:

What is obtained by the oxidation of isopropyl alcohol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module