The major product of the acetylation of salic | vedclass

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(B) $1$. Acetylation of salicylic acid with $Ac_2O/H^+$ yields acetylsalicylic acid (aspirin),where the phenolic $-OH$ group is acetylated to form an

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$5-$acetylsalicylic acid

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(B) $1$. Acetylation of salicylic acid with $Ac_2O/H^+$ yields acetylsalicylic acid (aspirin),where the phenolic $-OH$ group is acetylated to form an ester.$2$. Heating this ester with anhydrous $AlCl_3$ triggers a Fries rearrangement.$3$. In the Fries rearrangement of phenyl esters,the acyl group migrates from the phenolic oxygen to the ortho or para position of the benzene ring.$4$. Due to the presence of the bulky $-COOH$ group at the ortho position,steric hindrance makes the ortho-substitution less favorable.$5$. Therefore,the major product is the para-substituted isomer,which is $5$-acetylsalicylic acid (relative to the $-COOH$ group at position $1$ and $-OH$ at position $2$,the para position is $5$).

The major product of the acetylation of salicylic acid with $Ac_2O/H^+$ followed by heating with anhydrous $AlCl_3$ is

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