(D) According to Einstein's photoelectric equation, the maximum kinetic energy $(K_{max})$ of photoelectrons is given by: $K_{max} = h\nu - \Phi_0$ wh

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linearly with the frequency of incident radiation and is independent of its intensity.

(D) According to Einstein's photoelectric equation, the maximum kinetic energy $(K_{max})$ of photoelectrons is given by: $K_{max} = h\nu - \Phi_0$ where $h$ is Planck's constant, $\nu$ is the frequency of incident radiation, and $\Phi_0$ is the work function of the metal. From this equation, it is clear that $K_{max}$ varies linearly with the frequency $(\nu)$ of the incident radiation. Furthermore, the maximum kinetic energy is independent of the intensity of the incident radiation, as intensity only affects the number of photoelectrons emitted per unit time.

Class 12 Physics Dual Nature of Radiation and Matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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The maximum kinetic energy of the photoelectrons varies:

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A
inversely with the intensity of incident radiation and is independent of its frequency.
B
inversely with the frequency of incident radiation and is independent of its intensity.
C
linearly with the frequency of incident radiation and depends on its intensity.
D
linearly with the frequency of incident radiation and is independent of its intensity.

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Dual Nature of Radiation and Matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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$A$ photon released by the transition of an electron from the second excited state to the ground state of a Hydrogen atom is incident on the surface of a metal with a work function of $3.1 \ eV$. The de Broglie wavelength of the most energetic electron emitted from that metal surface is nearly:

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When a metal surface is illuminated by light of wavelength $\lambda$,the stopping potential is $8 \ V$. When the same surface is illuminated by light of wavelength $3 \lambda$,the stopping potential is $2 \ V$. The threshold wavelength for this surface is:

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Photoelectrons are emitted from a metal surface for frequencies $\nu_1$ and $\nu_2$. If the ratio of the maximum kinetic energy of the emitted photoelectrons is $1 : k$,then the threshold frequency of the metal surface is:

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The work function of a metal is $2.3 \text{ eV}$ and the maximum kinetic energy of photoelectrons is $0.3 \text{ eV}$ when a photon is incident on it. Find the wavelength of the incident photon in $\mathring A$.

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Monochromatic light of wavelength $\lambda$ is incident on an isolated metal sphere of radius $a$. The threshold wavelength is $\lambda_0$,which is greater than $\lambda$. How many photoelectrons will be emitted before the emission of photoelectrons stops?

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The maximum kinetic energy of the photoelectrons varies:

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$A$ photon released by the transition of an electron from the second excited state to the ground state of a Hydrogen atom is incident on the surface of a metal with a work function of $3.1 \ eV$. The de Broglie wavelength of the most energetic electron emitted from that metal surface is nearly:

When a metal surface is illuminated by light of wavelength $\lambda$,the stopping potential is $8 \ V$. When the same surface is illuminated by light of wavelength $3 \lambda$,the stopping potential is $2 \ V$. The threshold wavelength for this surface is:

Photoelectrons are emitted from a metal surface for frequencies $\nu_1$ and $\nu_2$. If the ratio of the maximum kinetic energy of the emitted photoelectrons is $1 : k$,then the threshold frequency of the metal surface is:

The work function of a metal is $2.3 \text{ eV}$ and the maximum kinetic energy of photoelectrons is $0.3 \text{ eV}$ when a photon is incident on it. Find the wavelength of the incident photon in $\mathring A$.

Monochromatic light of wavelength $\lambda$ is incident on an isolated metal sphere of radius $a$. The threshold wavelength is $\lambda_0$,which is greater than $\lambda$. How many photoelectrons will be emitted before the emission of photoelectrons stops?

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