The maximum velocity of a simple harmonic mot | vedclass

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Question

(A) The given equation for simple harmonic motion is $y = a \sin(\omega t + \phi)$,where $a$ is the amplitude and $\omega$ is the angular frequency.Co

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(A) The given equation for simple harmonic motion is $y = a \sin(\omega t + \phi)$,where $a$ is the amplitude and $\omega$ is the angular frequency.Comparing this with the given equation $y = 3 \sin \left( 100t + \frac{\pi}{6} ight)$,we get:Amplitude $a = 3$Angular frequency $\omega = 100 	ext{ rad/s}$.The maximum velocity $v_{\max}$ of a particle in simple harmonic motion is given by the formula $v_{\max} = a\omega$.Substituting the values,we get $v_{\max} = 3 	imes 100 = 300$.

The maximum velocity of a simple harmonic motion represented by $y = 3\sin \left( 100t + \frac{\pi}{6} \right)$ is given by

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