The mean deviation from the median for the fo | vedclass

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(C) First,we arrange the data in ascending order and calculate the cumulative frequency $(cf)$: $x_i: 2, 3, 5, 7, 9$ $f_i: 8, 6, 4, 2, 1$ $cf: 8, 14,

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$\frac{10}{7}$

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(C) First,we arrange the data in ascending order and calculate the cumulative frequency $(cf)$: $x_i: 2, 3, 5, 7, 9$ $f_i: 8, 6, 4, 2, 1$ $cf: 8, 14, 18, 20, 21$ Total frequency $N = \sum f_i = 21$. The median is the value corresponding to the $(\frac{N+1}{2})$-th observation,which is the $11$-th observation. From the $cf$ table,the $11$-th observation is $3$. So,$	ext{Median} (M) = 3$. Now,calculate the mean deviation about the median: $	ext{M.D.}(M) = \frac{\sum f_i |x_i - M|}{N}$ $|x_i - 3|: |2-3|=1, |3-3|=0, |5-3|=2, |7-3|=4, |9-3|=6$ $f_i |x_i - 3|: 8(1)=8, 6(0)=0, 4(2)=8, 2(4)=8, 1(6)=6$ $\sum f_i |x_i - 3| = 8 + 0 + 8 + 8 + 6 = 30$ $	ext{M.D.}(M) = \frac{30}{21} = \frac{10}{7}$.

Class interval	$0$-$10$	$10$-$20$	$20$-$30$	$30$-$40$	$40$-$50$	$50$-$60$	$60$-$70$
Frequency	$4$	$6$	$16$	$28$	$16$	$6$	$4$

The mean deviation from the median for the following data is
$x_i$ $2$ $3$ $5$ $7$ $9$
$f_i$ $8$ $6$ $4$ $2$ $1$

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The mean deviation from the median for the following data is $x_i$$2$$3$$5$$7$$9$$f_i$$8$$6$$4$$2$$1$